Physics - Geometrical Optics Question with Solution | TestHub

(P) Convex mirror (f = 10 cm, object at 30 cm): virtual, erect, diminished image. (Q) Plane air-water interface: virtual image of the same size. (R) Refraction at the spherical surface: $\frac{1.5}{v}-\frac{1}{-1}=\frac{1.5-1}{3}\Rightarrow v=-1.8\mathrm{m}$ (virtual), $m=\frac{n_{1}v}{n_{2}u}=\frac{1\times (-1.8)}{1.5\times (-1)}=\frac{6}{5}$ (magnified). (S) Silvered equiconvex lens: $f_{eq}=-5\mathrm{cm}$; with u = -20 cm, v = -20/3 cm: real and diminished. (T) Diverging lens (f = -10 cm, u = -10 cm): v = -5 cm: virtual and diminished. So A-S, B-P, Q, R, T, C-R, D-P, S, T. Hence option (A).