Physics - Geometrical Optics Question with Solution | TestHub

Minimum deviation $\delta$ when

$$\begin{array}{rlrlrlrlrlrlrlrl}& i=e& \delta =A& r_1+r_2=A\left(r_1=r_2=r\right)& 2r=A& \sin i=\mu \mathrm{sinr}& \sin i=\mu \sin \frac{A}{2}& \delta =1+e-A& A=2i-A& i=A& \sin A=\mu \sin \frac{A}{2}& 2\cos \frac{A}{2}=\mu & \cos \frac{A}{2}=\frac{\mu }{2}& 1-{\sin }^2\frac{A}{2}=\frac{{\mu }^2}{4}& {\sin }^2\frac{A}{2}=1-\frac{{\mu }^2}{4}& A=2{\sin }^{-1}\sqrt{\frac{4-{\mu }^2}{4}}\end{array}$$

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