Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceEasy2 minPYQ_2020

PhysicsEasysingle choice

Image of an object approaching a convex mirror of radius of curvature $20 m$ along its optical axis is observed to move from $\frac{25}{3} m$ to $\frac{50}{7} m$ in $30 s$ . If the object is moving uniformly, then its speed is

Options:

Answer:

Solution:

Using mirror formula,

Or $\frac{1}{u_{1}} = \frac{3}{25} - \frac{1}{10}$

Or $u_{1} = 50 m$

And

$∴ \frac{1}{u_{2}} = \frac{7}{50} - \frac{1}{10}$

Or $u_{2} = 25 m$

Speed of object $= \frac{u_{1} - u_{2}}{t i m e}$

$= \frac{25}{30} {m s}^{- 1}$

$= 3 k m h^{- 1}$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: PYQ_2020

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