Physics - Geometrical Optics Question with Solution | TestHub

Given $f=\frac{1}{3}$ m.

Since the image is real and inverted, magnification $m=-2$.

Using the formula for magnification of a lens, $m=\frac{v}{u}$, we get $v=-2u$.

Using the lens formula, $\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$.

Substituting the values:

$\frac{1}{-2u}-\frac{1}{u}=\frac{1}{1/3}$

$\frac{-3}{2u}=3$

$2u=-1\Rightarrow u=-0.5$ m.

The distance of the object from the lens is $0.5$ m.

Answer: 0.5 m