Physics - Geometrical Optics Question with Solution | TestHub

In $10 \mathrm{s}$, the object will travel distance $=2\times 10=20 \mathrm{cm}$

After $10 \sec$, the object will be at distance $u=20-100=-80 \mathrm{m}$.

Focal length of the concave mirror is  $f=\frac{R}{2}=\frac{200}{2}=-100 \mathrm{cm}$

Using mirror formula,

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

$\Rightarrow \frac{1}{v}=-\frac{1}{100}+\frac{1}{80}\Rightarrow v=\frac{8000}{20}$

$\Rightarrow v=400 \mathrm{cm}$

Position of image from the mirror is at $400 \mathrm{cm}$.