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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsEasy2 minPYQ_2024

PhysicsEasysingle choice

A small telescope has an objective of focal length 140 cm and an eye piece of focal length 5.0 cm . The magnifying power of telescope for viewing a distant object is:

Options:

Answer:

Solution:

$f_{0} = 140 cm$ and $f_{e} = 5 cm$ For distant object, $m = \frac{f _{0}}{f _{e}} = \frac{140}{5} = 28$

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: PYQ_2024

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