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PhysicsGeometrical OpticsRefraction at plane surfaceHard2 minPYQ_2022
PhysicsHardnumerical

A small bulb is placed at the bottom of a tank containing water to a depth of7 m. The refractive index of water is43. The area of the surface of water through which light from the bulb can emerge out isxπ m2. The value ofxis _____ .

Question diagram: A small bulb is placed at the bottom of a tank containing wa
Answer:
9.00
Solution:

Apply Snell's law, sin90°sinC=μ

sinC=1μRR2+h2=34



Squaring, 16R2=9R2+9h2

7R2=9h2R=37h=37×7=3 m

The area of the circle is, A=πR2=π32 m2α=9

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface
2mℹ️ Source: PYQ_2022

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