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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceEasy2 minPYQ_2021

PhysicsEasysingle choice

Car $B$ overtakes another car $A$ at a relative speed of $40 {m s}^{- 1}$ . How fast will the image of car $B$ appear to move in the mirror of focal length $10 cm$ fitted in car $A$ , when the car $B$ is $1.9 m$ away from the car $A$ ?

Options:

Answer:

Solution:

Object distance, $u = - 1.9 m = 190 cm$

Focal length, $f = 10 cm$

Magnification, $m = \frac{f}{f - u} = \frac{10}{10 - (- 190)}$

Therefore, $m = \frac{10}{200} = \frac{1}{20}$

Image velocity, $V_{I} = - m^{2} V_{0} = - {(\frac{1}{20})}^{2} \times 40$

Hence, $V_{I} = - 0.1 m s^{- 1}$

Magnitude of velocity $= 0.1 m s^{- 1}$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: PYQ_2021

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