Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsHard2 minPYQ_2024

PhysicsHardsingle choice

In normal adjustment, for a refracting telescope, the distance between objective and eye piece is 30 cm . The focal length of the objective, when the angular magnification of the telescope is 2 , will be:

Options:

Answer:

Solution:

$∵ f_{0} + f_{e} = 30$ And magnification, $m = \frac{f _{0}}{f _{e}}$ $2 = \frac{f _{0}}{f _{e}} \Rightarrow f_{0} = 2 f_{e} \Rightarrow f_{0} + \frac{f _{0}}{2} = 30 ∴ f_{0} = 20 c m$

Stream:BITSATSubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: PYQ_2024

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