Physics - Geometrical Optics Question with Solution | TestHub

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${\mathrm{\mu }}_{\mathrm{y}}=\frac{{\mathrm{\mu }}_{\mathrm{v}}+{\mathrm{\mu }}_{\mathrm{r}}}{2}$

$\Rightarrow {\mathrm{\mu }}_{\mathrm{y}}=\frac{1.5230+1.5145}{2}$

$\Rightarrow {\mathrm{\mu }}_{\mathrm{y}}=\frac{3.0375}{2}$

$\Rightarrow {\mathrm{\mu }}_{\mathrm{y}}=1.5187$

Therefore,

$\mathrm{\omega }=\frac{\left({\mathrm{\mu }}_{\mathrm{v}}-{\mathrm{\mu }}_{\mathrm{r}}\right)}{\left({\mathrm{\mu }}_{\mathrm{y}}-1\right)}$

$\Rightarrow \mathrm{\omega }=\frac{\left(1.5230-1.5145\right)}{\left(1.5187-1\right)}$

$\Rightarrow \mathrm{\omega }=\frac{0.0085}{0.5187}$

$\Rightarrow \mathrm{\omega }=0.0163°$