A spherical surface of radius of curvature ' R ' separates air from glass of refractive index 1.5. The centre of curvature is in the glass. A point object P placed in air forms a real image

Question

A spherical surface of radius of curvature ' R ' separates air from glass of refractive index 1.5. The centre of curvature is in the glass. A point object P placed in air forms a real image Q in the glass. The line PQ cuts the surface at point ' O ' and PO = OQ = x . Hence the distance ' x ' is equal to

TestHub · Accepted Answer

Given: u = − x , v = + x We know, ∴ ​ v n 2 ​ ​ − u n 1 ​ ​ = R n 2 ​ − n 1 ​ ​ ⇒ x 1.5 ​ + x 1 ​ = R 0.5 ​ x 2.5 ​ = R 0.5 ​ x = 5 R ​

Physics - Geometrical Optics Question with Solution | TestHub

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