Physics - Geometrical Optics Question with Solution | TestHub

As$n_2$decreases,$i_C={\sin }^{-1}\left(\frac{n_2}{n_1}\right)$also decreases.

So, condition$i>i_C$is still satisfied and there will be still total internal reflection at interface. If angle of incidence is increased, then ray will be still totally internally reflected at interface because$i>i_C$.