Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2020

PhysicsEasynumerical

A double convex thin lens made of the refractive index $1.6$ has radii of curvature $15 cm$ each. What is the focal length (in $cm$ ) of this lens when immersed in a fluid of refractive index $1.63$ ?

Answer:

-407.50

Solution:

Focal length of lens in given by

$\frac{1}{f_{w}} = (μ_{g} - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

$= (\frac{1.6}{1.63} - 1) (\frac{1}{15} + \frac{1}{15})$

$= - \frac{0.03 \times 2}{1.63 \times 15} = \frac{.0 6}{1.63 \times 15}$

$s o, f_{w} = - \frac{815}{2}$

$= - 407.5 cm$

Subject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2020

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