Physics - Geometrical Optics Question with Solution | TestHub

(A) Resolving power of the telescope $\mathrm{RP}=\frac{\mathrm{a}}{1.22\lambda }$ where a is the diameter (aperture) of the objective lens. $⟹\mathrm{RP}\propto \mathrm{a}$ Thus the aperture of the objective lens is made so large so as to increase the resolving power of the telescope.