Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at plane surfaceEasy2 minPYQ_2020

PhysicsEasysingle choice

A circular beam of light, of diameter $d = 2 cm$ , falls on a plane surface of a glass. The angle of incidence is $60^{o}$ and refractive index of glass is $µ = \frac{3}{2}$ . Find the approximate diameter of the refracted beam (in $cm$ ).

Options:

Answer:

Solution:

$d_{1} = P Q \cos 60^{o}$
$d_{2} = P Q \cos r$
$\frac{d_{1}}{d_{2}} = \frac{1}{2 \cos r}$

$d_{2} = 2 d_{1} \cos r$
$1 \times \sin i = µ \sin r$
$\sin r = \frac{\sin 60^{o}}{μ} = \frac{1}{\sqrt{3}} \Rightarrow \cos r = \sqrt{\frac{2}{3}}$
$d_{2} = 2 \times 2 \times \sqrt{\frac{2}{3}} = 3.26 c m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface

⏱ 2mℹ️ Source: PYQ_2020

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