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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2017

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The least distance of vision of a longsighted person is $60 cm$ . By using a spectacle lens, this distance is reduced to $12 cm$ . The power of the lens is

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Solution:

Using, $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$ Here, $v = - 60 cm, u = - 12 cm$ . $∴ \frac{1}{f} = \frac{1}{( - 60 )} - \frac{1}{( - 12 )} = \frac{- 1}{60} + \frac{1}{12} = \frac{1}{15} \frac{1}{f} = \frac{1}{15} \Rightarrow f = 15 cm$ Power, $P = \frac{100}{15} = \frac{20}{3} D$

Stream:AIIMSSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2017

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