Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2020

PhysicsEasysingle choice

A fish is near the centre of a spherical fishbowl filled with water ( $μ_{w} = \frac{4}{3}$ ). A child is standing at a distance of $2 R$ from the centre of the bowl, where $R$ is the radius of curvature of the bowl. The distance from the centre of the fishbowl, where the child's nose will appear to the fish is

Options:

Answer:

Solution:

$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R} \Rightarrow \frac{4}{3 v} - \frac{1}{- R} = \frac{\frac{4}{3} - 1}{R} \Rightarrow \frac{4}{3 v} = \frac{1}{3 R} - \frac{1}{R}$

$\frac{4}{3 v} = \frac{1 - 3}{3 R} \Rightarrow v = - \frac{4 R}{2} \Rightarrow v = - 2 R$

Distance of image from centre = 3R

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2020

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