Physics - Geometrical Optics Question with Solution | TestHub

Power of equiconvex lens $=P$ i.e $P=\frac{1}{f}$, where $f$ is focal length of equiconvex lens. When an equiconvex lens is cut into two symmetrical halves by a plane containing the principal axis, then its focal length remains same. Hence, power of lens (each halves) $\begin{array}{rl}& P^{\prime }=\frac{1}{f}\Rightarrow P^{\prime }=P\\ & \Rightarrow \frac{P^{\prime }}{P}=1\\ & \Rightarrow P:P=1:1\end{array}$