Physics - Geometrical Optics Question with Solution | TestHub

From Snell's law at first refraction,

${\mu }_{1}I=\mu r_1$

$r_1=I\frac{{\mu }_1}{\mu }$...(1)

From Snell's law at second refraction,

$\mu r_2={\mu }_{2}e$

$\mu \left(A-r_1\right)={\mu }_{2}e$

$\therefore$From (1),

$\mu \left(A-I\frac{{\mu }_1}{\mu }\right)={\mu }_{2}e$

$e=\frac{\mu }{{\mu }_2}\left(A-I\frac{{\mu }_1}{\mu }\right)$...(2)

Overall deviation,

$\delta =I+e-A$

$\delta =I+\frac{\mu }{{\mu }_2}\left(A-I\frac{{\mu }_1}{\mu }\right)-A$

$\delta =I\left(1-\frac{{\mu }_1}{{\mu }_2}\right)-A\left(1-\frac{\mu }{{\mu }_2}\right)$