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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsMedium2 minPYQ_2025

PhysicsMediumsingle choice

A microscope has an objective of focal length 2 cm , eyepiece of focal length 4 cm and the tube length of 40 cm . If the distance of distinct vision of eye is 25 cm , the magnification in the microscope is :

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Answer:

Solution:

$f_{0} = 2 cm L = 40 cm f_{e} = 4 cm D = 25 cm$ In the condition of normal adjustment. $m = \frac{L}{f _{0}} \cdot \frac{D}{f _{e}} = \frac{40}{2} \times \frac{25}{4} = 125$

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: PYQ_2025

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