A rectangular tank filled with some liquid is accelerated along a horizontal surface at 40 3 m s - 2 . Inside the liquid, a laser pointer is fixed a the centre of the tank which shoots a thin laser be

Question

A rectangular tank filled with some liquid is accelerated along a horizontal surface at 40 3 m s - 2 . Inside the liquid, a laser pointer is fixed a the centre of the tank which shoots a thin laser beam in the vertically upward direction. If after refraction from the liquid surface, the laser beam moves along the surface of the liquid, then what is the refractive index of the liquid?

TestHub · Accepted Answer

Due to the pseudo force, the free surface of the liquid will become inclined. If $θ$ is the angle made by the free surface of the liquid with the horizontal, then

$\tan θ = \frac{a}{g} = \frac{4}{3}$

$\Rightarrow \sin θ = \frac{4}{5}$

Using snell's law we get

$μ \sin θ = 1$

$μ = \frac{1}{\sin θ} = \frac{5}{4} = 1.25$

Physics - Geometrical Optics Question with Solution | TestHub

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