The refractive index of glass is 2 3 and that of water is 3 4 . The critical angle for a ray of light going from glass to water is

sin C 2 μ 1 sin C ∴ C = 2 μ 1 1 = μ 2 μ 1 = 4/3 3/2 = 2 3 × 4 3 = 8 9 = 9/8 1 = 9 8 = sin − 1 9 8

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionEasy2 minPYQ_2020

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The refractive index of glass is $\frac{3}{2}$ and that of water is $\frac{4}{3}$ . The critical angle for a ray of light going from glass to water is

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Solution:

$sin C_{2} μ_{1} sin C ∴ C = \frac{1}{2 μ _{1}} = \frac{μ _{1}}{μ _{2}} = \frac{3/2}{4/3} = \frac{3}{2} \times \frac{3}{4} = \frac{9}{8} = \frac{1}{9/8} = \frac{8}{9} = sin^{- 1} \frac{8}{9}$

Stream:MHT_CETSubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: PYQ_2020

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