Physics - Geometrical Optics Question with Solution | TestHub

$\frac{1}{f}=\left(\mu -1\right)\left[\frac{1}{10}+\frac{1}{10}\right]$

$=\left(\frac{2}{3}-1\right)\frac{2}{10}$

$=-\frac{1}{15} \Rightarrow f=-15$

This lens will behave like a biconcave lens.

So,  u = -5 cm

$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$

$\Rightarrow \frac{1}{\text{v}}-\frac{1}{-5}=\frac{1}{-15}$

$-\frac{1}{v}=\frac{1}{15}+\frac{1}{5}=\frac{4}{15}$

$\Rightarrow v=-3\text{.}7\mathrm{5 }\text{cm}$