Physics - Geometrical Optics Question with Solution | TestHub

For real inverted image formed by concave mirror.

$\text{v}=-\text{v}\text{e},\text{u}=-\text{v}\text{e},\text{f}=-\text{v}\text{e}$

$\Rightarrow \frac{\text{u}}{\text{f}} \& \frac{\text{v}}{\text{f}}\text{ are positive}$

So graph show be in 1st qudarant

$\text{and}\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$

$\Rightarrow \frac{\text{f}}{\text{v}}+\frac{\text{f}}{\text{u}}=1$

This graph can also be realized by Newtons formula${\text{x}}_1{\text{x}}_2={\text{f}}^2$where${\text{x}}_1\text{,}\text{ and }{\text{x}}_2$are distance from focus so graph will be rectangular hyperbola

$\Rightarrow$(1) is right answer.