Physics - Geometrical Optics Question with Solution | TestHub

For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is$i_1={\sin }^{-1}[\sin A\sqrt{4{\left(\cos \frac{A}{2}\right)}^2-1}-\cos A]$

For the angle of incidence$i_1=A$, the ray inside the prism is parallel to the base of the prism.

At minimum deviation, the incident angle$i_1$and the refracting angle$r_1$at the first refracting surface are related by$r_1=\left(\frac{i_1}{2}\right)$

For this prism, the refractive index$\mu$and the angle of prism$A$are related as$A=\frac{1}{2}{\cos }^{-1}\left(\frac{\mu }{2}\right)$