A compound microscope having magnifying power 35 with its eye-piece of focal length 10 cm . Assume that the final image is at least distance of distinct vision then the magnification produced by the o

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A compound microscope having magnifying power 35 with its eye-piece of focal length 10 cm . Assume that the final image is at least distance of distinct vision then the magnification produced by the objective is

TestHub · Accepted Answer

For a compound microscope, the magnifying power is given by

$M P = m_{e} \times m_{0}$

When the final image is at least distance of distance vision then

$M_{e} = 1 + \frac{D}{f_{e}}$

So, $M P = m_{0} [1 + \frac{D}{f_{e}}]$

$\Rightarrow - 35 = m_{0} [1 + \frac{25}{10}]$

$\Rightarrow - 35 = m_{0} \times 3.5$

$\Rightarrow m_{0} = -$ 10

The negative sign indicates that the image formed by objective is inverted.

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