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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsMedium2 minQB

PhysicsMediumsingle choice

A compound microscope has an objective of focal length 0.5 cm and an eyepiece of focal length 5 cm. What will be the angular magnification if tube length $= 7 cm$ , for the case in which the eye is least strained (LDDV = 20 cm)

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Answer:

Solution:

$v_{o} = L - f_{e} = 7 - 5 = 2 cm; 1/ u_{o} = 1/ f_{o} - 1/ v_{o} = 2 - 0.5 = 1.5 \Rightarrow u_{o} = 2/3 cm$ .

$m_{o} = v_{o} / u_{o} = 3; m_{e} = D / f_{e} = 20/5 = 4. m = 3 \times 4 = 12.$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: QB

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