Physics - Geometrical Optics Question with Solution | TestHub

For first refracting surface, For parallel beam of light; $-\frac{{\mu }_1}{u}+\frac{{\mu }_2}{V}=\frac{{\mu }_2-1}{R}$ $\begin{array}{rl}& \Rightarrow -\frac{1\cdot 4}{-\infty }+\frac{1\cdot 5}{V}=\frac{1\cdot 5-1.4}{R}\\ & V=15R\end{array}$ For second refracting surface, $\begin{array}{rl}& -\frac{{\mu }_2}{1.5R}+\frac{{\mu }_3}{V^{\prime }}=\frac{{\mu }_3-{\mu }_2}{R}\\ & \Rightarrow -\frac{1.5}{15R}+\frac{1.6}{V^{\prime }}=\frac{1.6-1.5}{R}\Rightarrow V^{\prime }=\infty \end{array}$ Hence, the combination behaves as glass plate.