Two concentric concave refracting surfaces of equal radii of curvature 35 cm and refractive index μ = 1.5 , face each other in air as shown. A point object is placed midway between their common center

Question

Two concentric concave refracting surfaces of equal radii of curvature 35 cm and refractive index μ = 1.5 , face each other in air as shown. A point object is placed midway between their common center and the pole of the right surface. What is the separation (in cm) between the images formed by refraction at these surfaces?

TestHub · Accepted Answer

Right surface ( R = − 35 cm, object 17.5 cm from P 2 ​ ): v 1.5 ​ = − 17.5 1 ​ + − 35 0.5 ​ gives the image 21 cm left of P 2 ​ , i.e. 14 cm right of C. Left surface (object 52.5 cm from P 1 ​ , R = − 35 cm): v 1.5 ​ = − 52.5 1 ​ − 35 0.5 ​ gives a virtual image 45 cm right of P 1 ​ , i.e. 10 cm right of C. Separation between the images: 14 − 10 = 4 cm.

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