Light travels from an optically denser medium 'A' into the optically rarer medium ′ B ′ with speeds 1 ⋅ 8 × 1 0 8 m / s and 2 − 7 × 1 0 8 m / s respectively. The critical angle between them is ( μ 1 and μ 2 are the refractive indices of media A and B respectively.)

μ B μ A = B μ A = V A V B = 1.8 × 1 0 8 2.7 × 1 0 8 = 2 3 B μ A = s i n C 1 ∴ 2 3 = s i n C 1 ∴ sin C = 3 2 or C = sin − 1 3 2

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minPYQ_2020

PhysicsMediumsingle choice

Light travels from an optically denser medium 'A' into the optically rarer medium $^{'} B^{'}$ with speeds $1 \cdot 8 \times 1 0^{8} m / s$ and $2 - 7 \times 1 0^{8} m / s$ respectively. The critical angle between them is $(μ_{1}$ and $μ_{2}$ are the refractive indices of media $A$ and $B$ respectively.)

Options:

Answer:

Solution:

$\frac{μ _{A}}{μ _{B}} =_{B} μ_{A} = \frac{V _{B}}{V _{A}} = \frac{2.7 \times 1 0 ^{8}}{1.8 \times 1 0 ^{8}} = \frac{3}{2}$ $_{B} μ_{A} = \frac{1}{s i n C}$ $∴ \frac{3}{2} = \frac{1}{s i n C}$ $∴ sin C = \frac{2}{3}$ or $C = sin^{- 1} \frac{2}{3}$

Stream:MHT_CETSubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: PYQ_2020

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