Physics - Geometrical Optics Question with Solution | TestHub

For a compound microscope, magnifying power $\mathrm{MP}={\mathrm{m}}_{\mathrm{e}}\times {\mathrm{m}}_0$ When the final image is at least distance of distance vision then $\begin{array}{rl}& {\mathrm{M}}_{\mathrm{e}}=1+\frac{\mathrm{D}}{{\mathrm{f}}_{\mathrm{e}}}\\ \therefore & \mathrm{MP}={\mathrm{m}}_0\left[1+\frac{\mathrm{D}}{{\mathrm{f}}_{\mathrm{e}}}\right]\\ \Rightarrow & -35={\mathrm{m}}_0\left[1+\frac{25}{10}\right]\\ \Rightarrow & -35={\mathrm{m}}_0\times 35\\ \Rightarrow & {\mathrm{m}}_0=-10\end{array}$ The negative sign shows that the image formed by objective is inverted.