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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceMedium2 minPYQ_2012

PhysicsMediumsingle choice

An object placed in front of a concave mirror at a distance of $x$ cm from the pole gives a 3 times magnified real image. If it is moved to a distance of $(x + 5) cm,$ the magnification of the image becomes 2 . The focal length of the mirror is

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Solution:

Given $y_{1} = 3 x$ and $v_{2} = 2 (x + 5)$ So here, Ist case $\frac{1}{- x} + \frac{1}{- 3 x} = \frac{1}{f} \frac{1}{- ( x + 5 )} + \frac{1}{- 2 ( x + 5 )} = \frac{1}{f}$ On solving Eqs. (i) and (ii) we get $f = 30 cm$

Stream:WBJEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: PYQ_2012

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