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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minPYQ_2011

PhysicsMediumsingle choice

A biconvex lens has a radius of curvature of magnitude $20 cm$ . Which one of the following options describe best the image formed of an object of height $2 cm$ placed $30 cm$ from the lens?

Options:

Answer:

Solution:

In general we have assumed $μ = 1.5$ So, $f = 20 cm$ $\frac{1}{f} \frac{1}{20} \frac{1}{y} y \frac{h _{i}}{h _{0}} h_{i} h_{i} = \frac{1}{y} + \frac{1}{u} = \frac{1}{y} + \frac{1}{30} = \frac{1}{20} - \frac{1}{30} = \frac{10}{600} = 60 cm = 2 = 2 \times ∣ h_{o} = 4 cm$ Here, Image is real, inverted, magnified field and height of image is $4 cm$ .

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2011

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