The Brewster's angle for the air-glass interface is $(54.74)^{\circ}$ . If a ray of light going from air to glass stikes at an angle of incidence $4 5^{0}$ , then the angle of refraction is
$(tan (54.74)^{0} = 2, sin 45 = 1 / 2)$

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According to Brewster's law, the refractive index of the medium is given by $μ = tan θ_{B}$ .

Substituting the given Brewster's angle, $μ = tan (54.7 4^{\circ}) = 2$ .

Using Snell's law for refraction from air to glass, $1 \cdot sin i = μ sin r$ .

Substituting $i = 4 5^{\circ}$ and $μ = 2$ , we get $sin 4 5^{\circ} = 2 sin r$ .

$\frac{1}{2} = 2 sin r$

$sin r = \frac{1}{2}$

$r = sin^{- 1} (\frac{1}{2})$

Answer: $sin^{- 1} (\frac{1}{2})$

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