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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceEasy2 minPYQ_2009

PhysicsEasysingle choice

In a concave mirror, an object is placed at a distance $d_{1}$ from the focus and the image is formed at a distance $d_{2}$ from the focus. Then the focal length of the mirror is

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Solution:

$U sing \frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ Given $u = f + d_{1} v = f + d_{2}$ $f = \frac{uv}{u + v} = \frac{( f + d _{1} ) ( f + d _{2} )}{( f + d _{1} ) + ( f + d _{2} )}$ On solving $f = d_{1} d_{2}$

Stream:AIIMSSubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

⏱ 2mℹ️ Source: PYQ_2009

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