Physics - Geometrical Optics Question with Solution | TestHub

Let $A^{\prime }$ be the angle of flint glass prism. Here, $\mathrm{A}=5^{\circ }$ and $\mu =1.51$ for crown glass prism. Deviation produced by flint glass, ${\delta }^{\prime }=(\mu -1)\mathrm{A}=(1.51-1)\times 5=2.55^{\circ }$ For no deviation, ${\delta }^{\prime }=\delta$ Or $0.65{\mathrm{A}}^{\prime }=2.55$ ${\mathrm{A}}^{\prime }=\frac{2.55}{0.65}=3.92^{\circ }$