The frequency of a light wave in a material is 2 × 1 0 14 Hz and wavelength is 5000 A ˚ . The refractive index of material will be.

Refractive index μ = V C = Vλ C = 2 × 1 0 10 × 5000 × 1 0 − 10 3 × 1 0 8 = 3

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at plane surfaceEasy2 minPYQ_2007

PhysicsEasysingle choice

The frequency of a light wave in a material is $2 \times 1 0^{14} Hz$ and wavelength is $5000 \overset{˚}{A}$ . The refractive index of material will be.

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Solution:

Refractive index $μ = \frac{C}{V} = \frac{C}{Vλ}$ $= \frac{3 \times 1 0 ^{8}}{2 \times 1 0 ^{10} \times 5000 \times 1 0 ^{- 10}} = 3$

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface

⏱ 2mℹ️ Source: PYQ_2007

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