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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minPYQ_2002

PhysicsMediumsingle choice

For the given incident ray as shown in the figure, the condition of the total internal reflection of this ray and the minimum refractive index of prism will be:

Options:

Answer:

Solution:

For given condition and use snell's law 1. $sin 4 5^{\circ} = μ sin (90 - q_{C})$ $\frac{1}{2} = μ cos θ_{C} = μ^{2} - 1 \Rightarrow μ^{2} = 1 + \frac{1}{2} = \frac{3}{2} \Rightarrow μ = \frac{3}{2}$ $∴ \Rightarrow cos θ_{c} = \frac{μ ^{2} - 1}{μ} sin θ_{c} = \frac{1}{μ}$

Stream:NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: PYQ_2002

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