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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensMedium2 minQB

PhysicsMediummultiple choice

. An object, which is at a distance of 30 cm from us, is observed through a lens. When the lens is kept very close to the object then the object seems to have its original size, but when the lens is in between observer and object at any position, size of image is greater than that of object.

Options:(select one or more)

Answer:

A, C

Solution:

$m = + 2 = \frac{v}{u} \Rightarrow v = 2 u$

$\frac{1}{2 u} - \frac{1}{u} = \frac{1}{f} u = - 30 \frac{1}{30} - \frac{1}{60} = \frac{1}{f} f = 60 cm$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: QB

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