Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensEasy2 minPYQ_2016

PhysicsEasysingle choice

A biconvex lens has a radius of curvature of magnitude $20 cm$ . Which one of the following options best describe the image formed of an object of height $2 cm$ placed $30 cm$ from the lens?

Options:

Answer:

Solution:

In the branch containing $L$ and $R_{2}$ $i = \frac{E}{R _{2}} (1 - e^{- \frac{R _{2} t}{L}}) \frac{di}{dt} = \frac{E}{R _{2}} e^{- \frac{R _{2} t}{L}} \cdot \frac{R _{2}}{L} = \frac{E}{L} e^{- \frac{R _{2} t}{L}} ∴ V_{L} = L \frac{di}{dt} = Ee^{- \frac{R _{2} t}{L}} = 12 e^{- \frac{2 t}{400 \times 1 0 ^{- 3}}} = 12 e^{- 5 t} V$

Stream:BITSATSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2016

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