A solid uniform ball of volume V floats on the interface of two immiscible liquids (figure). The specific gravity of the upper liquid is $ρ_{1}$ and that of lower one is $ρ_{2}$ and the specific gravity of ball is $ρ (ρ_{1} < ρ < ρ_{2})$ . The fraction of the volume of the ball in the upper liquid is :

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Balance the weight with the buoyant forces. V 1 ​ ρ 1 ​ g + V 2 ​ ρ 2 ​ g = V ρ g V 1 ​ + V 2 ​ = V V V 1 ​ ​ = ρ 2 ​ − ρ 1 ​ ρ 2 ​ − ρ ​ Option B.

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