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PhysicsFluidBernoulli's theorem and applicationsMedium3 minQB

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Passage / Comprehension

Torricelli's velocity of efflux is $v = 2 g h$ , where $h$ is the height of the liquid above the hole. After leaving the hole, treat the flow as projectile motion.
The two vessel configurations (i) and (ii) are shown below.

At what distance from point O , will be liquid strike on the ground?

Options:

Answer:

Solution:

The outlet lies $O A = 2 cos 3 0^{\circ} = 3 m$ horizontally from O.
From the earlier questions, $v = 4.96 m/s$ and $t = 1/ 5 s$ .
Horizontal flight distance $A B = v t$
$A B = \frac{4.96}{5} ≃ 2.22 m$ .
So $OB = O A + A B$
$OB = 1.73 + 2.22 = 3.95 m$ . Answer: D.

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Bernoulli's theorem and applications

⏱ 3mℹ️ Source: QB

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