Physics - Fluid Question with Solution | TestHub

Pressure at bottom of the lake$={\text{P}}_0+\text{h}\rho \text{g}$
and pressure at half the depth of a lake

$={\text{P}}_0+\frac{\text{h}}{2}\rho \text{g}$

According to given condition

$={\text{P}}_0+\frac{1}{2}\rho \text{g}=\frac{2}{3}\left({\rho }_0+\text{h}\rho \text{g}\right)$

$\Rightarrow \text{h}=\frac{2{\text{P}}_0}{\rho \text{g}}=\frac{2\times 10^5}{10^3\times 10}=20\text{m}$