Physics - Fluid Question with Solution | TestHub

The vertical height $h$ to which water rises in a capillary tube is given by

$h=\frac{2T\cos \theta }{r\rho g}$

Substituting the given values:

$h=\frac{2\times 7\times 10^{-2}\times 1}{0.35\times 10^{-3}\times 1000\times 10}$

$h=\frac{14\times 10^{-2}}{3.5}=0.04\text{ m}=4\text{ cm}$

When the capillary tube is inclined at an angle $\alpha$ with the vertical, the vertical height of the liquid column remains the same. If $l$ is the length of the water column in the inclined tube, then

$h=l\cos \alpha$

$l=\frac{h}{\cos 60^{\circ }}$

$l=\frac{4}{0.5}=8\text{ cm}$

Answer: 8 cm