Physics - Fluid Question with Solution | TestHub

The correct option is (D). Concept: Surface Energy is proportional to the surface area $\mathrm{E}\propto 4\pi R^2$. Considering volume conservation, the size of small droplets $r$ is: $V=\frac{4}{3}\pi R^3=216\times \frac{4}{3}\pi r^3$ Therefore, $\mathrm{R}=6\mathrm{r}$ The total surface area of the new 216 droplets is: $216\times \left(4\pi r^2\right)$ or $6\times \left(4\pi R^2\right)$ Given $E\propto 4\pi R^2$ Therefore, the total surface energy of the new droplets would be $6\mathrm{E}$