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PhysicsFluidBernoulli's theorem and applicationsMedium2 minPYQ_2021

PhysicsMediumsingle choice

Two narrow bores of diameter $5.0 mm$ and $8.0 mm$ are joined together to form a $U -$ shaped tube open at both ends. If this $U -$ tube contains water, what is the difference in the level of two limbs of the tube.
[Take surface tension of water $T = 7.3 \times 10^{- 2} N m^{- 1}$ , angle of contact $= 0, g = 10 {m s}^{- 2}$ and density of water $= 1.0 \times 10^{3} kg m^{- 3}]$

Options:

Answer:

Solution:

$P_{0} - \frac{2 T}{R_{1}} + h_{1} ρ g = P_{0} - \frac{2 T}{R_{2}} + h_{2} ρ g$
$(h_{1} - h_{2}) ρ g = 2 T [\frac{1}{2.5 \times 10^{- 3}} - \frac{1}{4 \times 10^{- 3}}] \Rightarrow h_{1} - h_{2} = 2.19 mm$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Bernoulli's theorem and applications

⏱ 2mℹ️ Source: PYQ_2021

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