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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

A drop of mercury of radius $2 mm$ is split into $8$ identical droplets. Find the increase in surface energy. (Surface tension of mercury is $0 .465 J m^{- 2}$ )

Options:

Answer:

Solution:

Increase in surface energy or work done in splitting a big drop $= 4 π R^{2} T (n^{1 / 3} - 1)$ $\Rightarrow W = 4 π \times {(2 \times 10^{- 3})}^{2} \times 0.465 (8^{1 / 3} - 1) = 23.4 μJ$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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