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PhysicsFluidBernoulli's theorem and applicationsEasy2 minPYQ_2020

PhysicsEasysingle choice

A horizontal pipeline carries water in streamline flow. At a point where the cross-sectional area is $10 {cm}^{2}$ the water velocity is $1 m s^{- 1}$ and pressure is $2000 Pa$ . The pressure of water at another point where the cross-sectional area is $5 {cm}^{2}$ , is

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Answer:

Solution:

Since the cross-sectional area is halved, therefore, velocity is doubled.

Now, $p_{1} = 2000 P a, v_{1} = 1 m s^{- 1}$

$p_{2} = ?, v_{2} = 2 m s^{- 1}$

${A g a i n p}_{2} + \frac{1}{2} \times 1000 \times 2 \times 2 = 2000 + \frac{1}{2} \times 1000 \times 1 \times 1$

$o r p_{2} = 2000 + 500 (1 - 4) = 500 P a$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Bernoulli's theorem and applications

⏱ 2mℹ️ Source: PYQ_2020

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