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PhysicsFluidPressureEasy2 minPYQ_2024

PhysicsEasynumerical

Mercury is filled in a tube of radius $2 cm$ up to a height of $30 cm$ . The force exerted by mercury on the bottom of the tube is _____ N. (Given, atmospheric pressure $= 1 0^{5} Nm^{- 2}$ , density of mercury $= 1.36 \times 1 0^{4} kg m^{-}$ $^{3}, g = 10 m s^{- 2}, π = \frac{22}{7})$

Answer:

177.00

Solution:

$F = P_{0} A + ρ_{m} ghA = 1 0^{5} \times \frac{22}{7} \times (2 \times 1 0^{- 2})^{2} + 1.36 \times 1 0^{4} \times 10 \times (30 \times 1 0^{- 2}) (\frac{22}{7} \times (2 \times 1 0^{- 2})^{2}) F = 51.29 + 125.71 = 177 N$

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Pressure

⏱ 2mℹ️ Source: PYQ_2024

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