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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionEasy2 minPYQ_2020

PhysicsEasysingle choice

The radii of two soap bubbles are $r_{1}$ and $r_{2}$ . In isothermal conditions, two meet together in a vacuum. Then the radius of the resultant bubble is given by

Options:

Answer:

Solution:

Apply mole conservation
$\begin{array}{l} n_{1} + n_{2} = n \\ P_{1} V_{1} + P_{2} V_{2} = P V \end{array}$
outside pressure is zero
$\begin{array}{l} (\frac{4 S}{r_{1}}) \frac{4}{3} π {r_{1}}^{3} + \frac{4 S}{r_{2}} \frac{4}{3} π {r_{2}}^{3} = \frac{4 S}{R} \frac{4}{3} π R^{3} \\ {r_{1}}^{2} + {r_{2}}^{2} = R^{2} \end{array}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 2mℹ️ Source: PYQ_2020

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